tanx =3/4 find 4cos2x+3sin2x
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Divide and multiply the given statement by 5,we get
5(4/5cos x +3/5sin x)
Now,let sin A=4/5 then automatically cos A=3/4. (as sin^2 x +cos^2 x =1)
So, the statement will become
5(sin A cos x +cos A sin)
5 sin(A + x)
Maximum value of sin y can be 1.
Therefore, maximum value of 5 sin(A + x) is 5.
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Igor Belkov (Игорь Бельков)
, studied at Saint-Petersburg State University
Answered Apr 23, 2018
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