Question

tanx-5x\6x+sin3x limit x_0

Answer 1

just keep in mind if X tends to zero then
sinx/x=1
and tanx/x=1
$( \tan(x) - 5x) \div (6x + \sin(3x)) \\ ((x \tan(x) \div x) - 5x) \div (6x + (3x \sin(3x) \div 3x)) \\ (x - 4x) \div (6x + 3x) \\ = ( - 3x) \div (9x) \\ = - (1 \div 3)$
here is your answer.... mark as brainliest if helped