Question

(tanx+cotx)^2=sec^2x+cosec^2x

Answer 1

❤❤here is your answer ✌ ✌ ✌ In attachment

Answer 2

Step-by-step explanation:

$LHS = ( tan x + cot x )^{2}\\= tan^{2} x + 2tanx cotx + cot^{2} x$

$\boxed { \pink { Since , \:(a+b)^{2} = a^{2} + 2ab + b^{2}}}$

$</p><p>[tex] = tan^{2} x + 2\times 1 + cot^{2} x$

$\boxed { \pink { tanx cotx = 1 }}$

$= ( 1+ tan^{2} x ) + ( 1 + cot^{2} x )$

$= sec^{2} x + cosec^{2} x \\= RHS$

Therefore.,

$Hence , \: proved$

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