tanx /sec2x is the ans
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Solution :
tanx/( sec²x)
= ( sinx/cosx)/( 1/cos²x )
= ( sinx/cosx )( cos²x/1 )
After cancellation, we get
= Sinxcosx
= ( 2sinxcosx )/2
= ( sin2x )/2
[ Since ,
2sinxcosx = sin2x ]
••••
tanx/( sec²x)
= ( sinx/cosx)/( 1/cos²x )
= ( sinx/cosx )( cos²x/1 )
After cancellation, we get
= Sinxcosx
= ( 2sinxcosx )/2
= ( sin2x )/2
[ Since ,
2sinxcosx = sin2x ]
••••
ayush4982:
but prove ma toh tanx ara h
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