Question

(tanx)^sinx use logarithmic differentiation

Answer 1

y=(tanx)^sinx
dy/dx=sinx.log tanx

we use the formula du.v /dx=v.du/dx+u.dv/dx

here u=sinx , v=log tanx

now using the formula....
dy/dx=log tanx.cosx+sinx.1/tanx.sec^2 x