Question

Tanx + tan2x +tan3x = tanxtan2xtan3x then |sin3x+cos3x|

Answer 1

Answer:

Step-by-step explanation:

=sin²cos³2tan³

Answer 2

Answer:

1

Step-by-step explanation:

Tan 3x=tan(2x+x)

Tan3x=tan2x+tanx/1-tan2xtanx

Tan3x(1-tan2xtanx)=tan2x+tanx

Therefore, tan3x-tan2x-tanx= tan3x+tan2x+tanx

2tan^2x+2tanx=0

Tan2x+tanx=0

sin2x/cos2x+sinx/cosx=0

Sin^2xcosx+cos2xsinx/cos2xcosx=0

Sin(2x+x)/cos2xcosx=0

Sin3x=0

Sin^23x+cos^3x=1

Cosx=+1or-1, sinx=0

Hence,|sin3x+cosx|=1