(tanx/x)ln((e^x)/(x^x))
Confused about how it is −(ln(x)−1)tan(x)
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Answer:
tanx)(1-lnx)
Step-by-step explanation:
tanx/x)(lne^x-lnx^x)
tanx/x)(x-xlnx)
we get the answer by taking x common
use lna^x=xlna
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