Math, asked by SANKALP2632, 10 months ago

Tanya and vihaan together sold tickets for the school feet for rupees 3200 if Tanya sold 1 mixed 2/3 times the tickets sold by vihaan then find the worth of tickets sold by each of them?

Answers

Answered by ms82096741
4

Answer:

Let Tea A and B be sold at Rs.a and Rs.b respectively

When A and B are mixed in the ratio 3 : 2 and sold at a profit of 10% at Rs.40 per Kg

3a+2b53a+2b5 = 401.1401.1 ------(1)

When A and B are mixed in the ratio 2 : 3 and sold at a profit of 5% at Rs.40 per Kg

2a+3b52a+3b5 = 401.05401.05 ------(2)

Solving equations (1) and (2), we get

1.1 × (3a+2b53a+2b5) = 1.05 × (2a+3b52a+3b5)

11101110 × (3a + 2b) = 21202120 × (2a + 3b)

66a + 44b = 42a + 63b

24a = 19b

abab = 19241924

So, the cost prices per Kg of A and B are in the ratio 19 : 24

Answered by aksharagupta619
2

Answer:

this answer is wrong

Step-by-step explanation:

answer is tanay sold tickets with 2000, Vihaan sold tickets with 1200

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