Math, asked by DNYANEAHWRI4519, 1 year ago

Tanya had rupees 50 . How many chocolates can she buy if the cost of 1 chocolate is rupees 8and1by3?

Answers

Answered by BrainlySmile
21
Answer- Amount of money Tanya has= ₹50
Cost of 1 chocolate=
₹8 1/3= ₹25/3
No. of chocolates that she can buy=
₹50÷₹25/3
                                                       =
₹50×₹3/25
                                                       = 2×3 (after Simplification)
                                                       = 6 chocolates
So, Tanya can buy 6 chocolates with
₹50.
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Answered by Ananya2893
2

Answer:

Step-by-step explanation:

Answer- Amount of money Tanya has= ₹50

Cost of 1 chocolate= ₹8 1/3= ₹25/3

No. of chocolates that she can buy= ₹50÷₹25/3

                                                      = ₹50×₹3/25

                                                      = 2×3 (after Simplification)

                                                      = 6 chocolates

So, Tanya can buy 6 chocolates with ₹50.

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