Math, asked by deborahyang, 9 months ago

Tanya has a garden with a trench around it. The garden is a rectangle with length 2 \dfrac12 \text{m}2
2
1

m2, start fraction, 1, divided by, 2, end fraction, start text, m, end text and width 2 \text{ m}2 m2, start text, space, m, end text. The trench and garden together make a rectangle with length 3 \dfrac12 \text{m}3
2
1

m3, start fraction, 1, divided by, 2, end fraction, start text, m, end text and width 3 \text{ m}3 m3, start text, space, m, end text.
Find the area of just the trench.
\text{m}^2m
2
start text, m, end text, squared

Answers

Answered by abisoyi2004
1

Answer:

Step-by-step explanation:

(i) Here, P(2) = k

⇒ 23 + 3(2)2 – k(2) + 4 = k

⇒ 8 + 12 – 2k + 4 = k

⇒ 3k = 24

⇒ k = 8

(ii) Here,

⇒ p(-3)3 + 9(- 3)2 + 4(- 3) – 10 = 5

⇒ - 27p + 81 – 12 – 10 = 5

⇒ - 27p = - 54

⇒ p = 2

Answered by mbus7718
1

Answer: the area of the trench is 11/2 m^2

Step-by-step explanation: let's draw the diagram of the trench.

area of the garden= lenght x width

                                = 2 and half ⋅ 2

                                = 5/2 ⋅ 2

                                 =5m^2

area of the garden and trench = lenght ⋅ width

                                                    = 3 and half ⋅ 3

                                                    = 7/2 ⋅ 3

                                                     = 21/2 m^2

lets subtract the aea if the garden from the area of the garden and the trench to find the trench:

21/2 - 5

=21/2 -10/2

=11/2

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