tanya has rupees 50 how many chocolates can she buy if the cost of 1 chocolate is rupees 8and1by3?
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Answer- Amount of money Tanya has= ₹50
Cost of 1 chocolate= ₹8 1/3= ₹25/3
No. of chocolates that she can buy= ₹50÷₹25/3
= ₹50×₹3/25
= 2×3 (after Simplification)
= 6 chocolates
So, Tanya can buy 6 chocolates with ₹50.
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Pl. mark as the BRAINLIEST answer..
Cost of 1 chocolate= ₹8 1/3= ₹25/3
No. of chocolates that she can buy= ₹50÷₹25/3
= ₹50×₹3/25
= 2×3 (after Simplification)
= 6 chocolates
So, Tanya can buy 6 chocolates with ₹50.
------------------------------------------------------------------------
Pl. mark as the BRAINLIEST answer..
neela112:
thanks
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Amt of money Tanya has= ₹50
Cost of 1 chocolate= ₹8 1/3= ₹25/3
No. of chocolates that she can buy= ₹50÷₹25/3
= ₹50×₹3/25
= 2×3 (after Simplification)
= 6 chocolates
So, Tanya can buy 6 chocolates with ₹50.
Cost of 1 chocolate= ₹8 1/3= ₹25/3
No. of chocolates that she can buy= ₹50÷₹25/3
= ₹50×₹3/25
= 2×3 (after Simplification)
= 6 chocolates
So, Tanya can buy 6 chocolates with ₹50.
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