Math, asked by neela112, 1 year ago

tanya has rupees 50 how many chocolates can she buy if the cost of 1 chocolate is rupees 8and1by3?

Answers

Answered by BrainlySmile
4
Answer- Amount of money Tanya has= ₹50
Cost of 1 chocolate=
₹8 1/3= ₹25/3
No. of chocolates that she can buy=
₹50÷₹25/3
                                                       =
₹50×₹3/25
                                                       = 2×3 (after Simplification)
                                                       = 6 chocolates
So, Tanya can buy 6 chocolates with
₹50.
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neela112: thanks
Answered by 312103
0
Amt of money Tanya has= ₹50
Cost of 1 chocolate= ₹8 1/3= ₹25/3
No. of chocolates that she can buy= ₹50÷₹25/3
= ₹50×₹3/25
= 2×3 (after Simplification)
= 6 chocolates
So, Tanya can buy 6 chocolates with ₹50.
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