Tanya invested rs 4800 at the rate of X%p.a.and rs 2400 at the rate of 2X p.a.each on compound interest. If she gets Rs. 48 more interest on the amount invested at 2X% than amount invested at X% after two years, then find the value of (x/2)%?
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(x/2)% = 5 %
Step-by-step explanation:
Tanya invested rs 4800 at the rate of X%p.a
Interest in 2 Years = 4800 ( 1 + X/100)² - 4800
= 4800 ( X²/10000 + 2X/100)
= 48(X²/100 + 2X)
rs 2400 at the rate of 2X p.a
Interest in 2 Years = 2400 ( 1 + 2X/100)² - 2400
= 2400 ( 4X²/10000 + 4X/100)
= 96(X²/100 + X)
96(X²/100 + X) = 48(X²/100 + 2X) + 48
=> 2(X²/100 + X) = (X²/100 + 2X) + 1
=> 2X²/100 + 2X = X²/100 + 2X + 1
=> X²/100 = 1
=> X² = 100
=> X = 10
X/2 = 5
(x/2)% = 5 %
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