Question

Tanya leaves her home at 1:30 p.m. and drives

at an average of 40 mph and then stops at 3:00

p.m. If Max needs to travel half the distance to

meet Tanya at 3 p.m., how fast must he drive if

he leaves at 2 p.m.?​

Answer 1

Answer:

Distance covered by tanya by 2 pm = 1/2 hr x 40 km/hr

= 20 kms.

Relative speed of tanya and max would be;

= (50 - 40)

10 km/hr

Time required for max to catch up = 20 km / 10 km/hr = 2 hr

So max should travel at a speed of 50 km/h to catch up with tanya at 4 pm.

Answer 2

Step-by-step explanation:

$answer$

$= 2 \times \frac{4}{8}$

$= 2 \times 4 \div 8$

$= 8 \div 8$

$= 0$