Math, asked by Ikkdn2016, 1 month ago

Tap A and Tap B fill a cistern in 8 hours and 10 hours , respectively. The full

cistern can be emptied by Tap C in 9 hours. If all the taps are turned on at

the same time, in how much time will the empty cistern be filled up

completely? Show your work. I NEED STEP BY STEP EXPLAINATION I MARK AS BRANILIST AMNSWER

Answers

Answered by ishita753
1

Answer:

27 hours

Step-by-step explanation:

Tap A fills cistern = 8hours

Tap B fills cistern = 10hours

Tap C empties cistern = 9hours

If all the taps are open cistern will be filled in:

=Tap A +Tap B + Tap C

=8 + 10 +9

= 27 hours

Therefore the cistern will take 27 hours to fill..

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Answered by 3636rohitbankoti25
1

Step-by-step explanation:

Part of cistern filled by Tap A = 1/8

Part of cistern filled by Tap B = 1/10

Part of cistern filled by Tap C = 1/9

= 1/8 + 1/10 -1/9

= 45+36-40/360

= 41/360

cistern will be filled in 360/41

= 8.78hours

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