Question

tap A can fill 1/4 of a tank in 12 hours and tap B can fill 1/6 of a tank in 6 hours .How long will it take to fill the tank completely if both the taps are opened together ?
Hint : 144 / 7 answer​

Answer 1

Step-by-step explanation:

A fill 1/4 th tank in 12 hours so

Total time in which tap A will fill the tank

$= 12 \times 4 = 48 \: hrs$

Similarly total time in which B alone fills the tank

$= 6 \times 6 = 36 \: hrs$

Let the time taken to fill the tank when both taps are opened together is t , so

$\frac{1}{t} = \frac{1}{48} + \frac{1}{36} \\ \\ \implies \frac{1}{t} = \frac{3 + 4}{144} = \frac{7}{144} \\ \\ \implies \: t = \frac{144}{7} \: hrs$

Answer 2

Answer:

$\large \dag$ Question :-

Tap A can fill 1/4 of a tank in 12hours and tap B can fill 1/6 of a tank in 6hours .How long will it take to fill the tank completely If both taps are opened together .

$\large \dag$ Answer :-

$\sf\tt\large{\red {\underline {\underline{\;It \;requires \;144/7 \;hours \;long \;it \;will \;take \;to \;fill \;the \;tank \;completely \;if \;both \;taps \;are \;opened \;together:}}}}$

$\large \dag$ Solutions :-

Hey mate ,

After verifying your question we come to know that,

First ,

we should take the t1 and t2 values [t1&t2=time taken ]

Here,

According to the given question,

t1 in which the tap A will fill the tank is ,

• t1 =12 ×4 =48hours

Next,

According to the given question,

t2 in which the tap B will fill the tank will be

• t2 = 6×6=36 hours .

Now,

Here we know one formula to find the total time according to your question. that is ,

$\frac{1}{t} = \frac{1}{t1} + \frac{1}{t2}$

But,

Here already know the values lets apply to the given formula we get that,

• $\frac{1}{t} = \frac{1}{48 } + \frac{1}{28}$

• 3+4/144 = 7/144

• t = 144/7hours .[here taking reciprocal] we get the value .

Therefore,

This is the perfect answer to your question..

$\large \dag$ Hope it helps u mate .

$\large \dag$ Thank you .