Tap a can fill a cistern in 12 hours, b in 10 hours and c in 15 hours. they all are opened together, but a is closed after 2 hours of starting and b is closed 3 hours before the cistern to be filled. in how much time will the cistern be filled?
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Given: Tank of volume X
Constant flowrates (tank volumes per hour)
A=X/3
B=X/5
C= -X/7 1/7
Find: t the time in hours to fill the tank
Solution:
(A + B + C) * t= X
(X/3 + X/5 -X/7 1/7) * t= X
(X/3 + X/5 - 7X/50) * t = X
((50 X + 30X -21X)/150) * t = X
(59X/150) *t = X
Divide both sides by X
59/150 * t = 1
t = 1/(59/150)
t= 150/59
Therefore the time to fill the tank is 150/59 hours or 2.54 hours
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the time to fill the tank is 2.54 hours
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