Math, asked by vibhaupadhyay72, 5 months ago

Tap A can fill a cistern in 5 hours. Tap B can fill the cistern in 4 hours. Both the taps are opened
together. After two hours, tap B is closed. How long will tap A take to fill the remaining cistern?​

Answers

Answered by samanwaybagchi
4

Answer:

30 MINUTES IS THE CORRECT ANSWER.

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Answered by sckbty72
5

Answer:

30 min

Step-by-step explanation:

Let the work done be unity.

A takes 5 hrs to do the work.

So, work done by A in 1 hr = 1/5

B takes 4 hrs to do the work.

So, work done by B in 1 hr = 1/4

Work done by A and B together in 1 hr = 1/5 + 1/4 = 9/20

So, work done by both in 2 hrs = 2*9/20 = 9/10

Work left = 1 - 9/10 = 1/10

So time taken by A to do this work (in hrs) = (1/10)/(1/5) = 1/2

So, he requires 30 min to fill the remaining cistern

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