Tap A can fill a cistern in 5 hours. Tap B can fill the cistern in 4 hours. Both the taps are opened together. After two hours, tap B is closed. How long will tap A take to fill the remaining cistern?
Answers
Given that Tap A can fill a cistern in 5 hours.
Part of the cistern filled in 1 hour by A = (1/5).
Given that Tap B can fill a cistern in 4 hours.
Part of the cistern filled in 1 hour by B = (1/4).
-----------------------------------------------------------------------------------------------------------------
Given that after 2 hours, tap B is closed.
Work done by B in 2 hours = 2(1/5 + 1/4) = 9/10.
Remaining part = 1 - 9/10 = 1/10.
Now,
Tap A to fill the cistern in = (1/10) * 5
= > 5/10
= > 1/2 hours
= > 30 minutes.
Therefore, Remaining part is filled by A in 30 minutes.
Hope this helps!
Answer:
Step-by-step explanation:
Given that Tap A can fill a cistern in 5 hours.
Part of the cistern filled in 1 hour by A = (1/5).
Given that Tap B can fill a cistern in 4 hours.
Part of the cistern filled in 1 hour by B = (1/4).
-----------------------------------------------------------------------------------------------------------------
Given that after 2 hours, tap B is closed.
Work done by B in 2 hours = 2(1/5 + 1/4) = 9/10.
Remaining part = 1 - 9/10 = 1/10.
Now,
Tap A to fill the cistern in = (1/10) * 5
= > 5/10
= > 1/2 hours
= > 30 minutes.
Therefore, Remaining part is filled by A in 30 minutes.