Tap a can fill a cistern in 8 hours and tap b can empty it in 12 hours . How long it will take to fill the cistern if both of them are opened together
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Given:-
- Tap a can fill a cistern in 8 hours.
- Tap b can empty it in 12 hours.
To Find:-
- Time required to fill the cistern if both of them are opened together.
Solution :-
Tap a can do 1/8 work in 1 hour.
And tap b can do 1/12 work in 1 hour.
So,
Total work done by both the types when they are poened together = work done by tap a + work done by tap b.
Total work = 1/8 + (-1/12)
Total work = 1/8 - 1/12
Total work = 1/24
Hence, 24 hours will be taken by both the taps.
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