Tap A can fill a tank in 10 hours, while tap B can empty the tank in 12 hours, If bon
the taps are opened together in the empty tank, in how many hours will the tank you
filled?
Answers
Answer:
60 hour's
Step-by-step explanation:
time taken by tap a to fill the tank = 10 hrs
work done by tap a in 1 hour =1/10
time taken by tap b to empty the tank =12 hours
work done by tap b in 1 hour = 1/12
work done by tap b in 1 hour = 1/10 -1/12= 6-5/60 = 1/60
therefore the time taken by the two taps to fill the tank 60 hours .
Answer:
Let, the total volume of the tank be x litres.
In case of first tap,
in 12 hrs, it supplies x litres of water
So, in 1 hr it supplies x/12 litres of water
And, in case of 2nd tap,
in 10 hrs, it removes x/2 litres of water
In 1 hr, it removes x/20 litres of water
Therefore after 1 hr the ultimate amount of water remaining in the tank, when both the taps are on..
=X/12-X/20.
=x/30
Let the required number of hours be Y
Then (x/30)*Y=X
Y=30 hrs (ans)
Step-by-step explanation:
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