Math, asked by ashayadav1981ad, 7 months ago

Tap A can fill a tank in 12 hrs while tap B can fill it in 15 hrs. If both the taps are opened together and after 3 hrs tap B is closed then in how much time will tap A take to fill the remaining tank​

Answers

Answered by vrkinage68
1

Answer:

Step-by-step explanation:

Let us name the 3 Taps be T  

A

​  

,T  

B

​  

,T  

C

​  

 

where T  

B

​  

,T  

C

​  

 are emptying pipes and T  

A

​  

 is filling Pipe.

Water Emptied by T  

B

​  

 in 6 hours=Volume of Tank or V

Water Emptied by T  

B

​  

 in 1 Hour=  

6

V

​  

 

Similarly, Water Emptied by T  

C

​  

 in 8 Hour=V  

Water Emptied by T  

C

​  

 in 1 Hour=  

8

V

​  

 

Similarly, Water Supplied by T  

A

​  

 in 2 Hour=V  

Water Supplied by T  

A

​  

 in 1 Hour=  

2

V

​  

 

After 2 Hours,

⇒2  

2

V

​  

−2  

8

V

​  

−2  

6

V

​  

=  

12

5V

​  

 

After 3 Hours,

⇒  

12

5V

​  

+  

2

V

​  

−  

6

V

​  

=  

4

3V

​  

 

 

Now, only T  

A

​  

 is opened  

Remaining Volume=V−  

4

3V

​  

 =  

4

V

​  

 

Now Time taken to Fill Remaining Tank

⇒  

2

V

​  

 

4

V

​  

 

​  

=  

2

1

​  

hrs=30min

Therefore Answer is (C)

Similar questions