Tap A can fill an empty tank in 6-hours and Tap B can empty the full tank in 8-hours. If
the tank is empty when tap A is opened at 9:00 am and tap B is opened at 11:00 am,
then at what time is the tank filled
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In 1 hour
Tap A = 1/6 ( of the work) in 1 hour
Tap B = -1/8 (of the work)
Now lets Assume
Tap B is opened for x hours
Tap A is opened 2 hours earlier;
Hence tap A is opened for x + 2 hours
1/6( x+2) - 1/8 x = x
x/6 + 1/3 - x/8 = x
(4x - 3x - 24 x )/24 = -1/3
-23x/24 = -1/3
x = 1/3 * 24/23 = 8/23approx 20 mins
Time it is filled
11: 20
Tap A = 1/6 ( of the work) in 1 hour
Tap B = -1/8 (of the work)
Now lets Assume
Tap B is opened for x hours
Tap A is opened 2 hours earlier;
Hence tap A is opened for x + 2 hours
1/6( x+2) - 1/8 x = x
x/6 + 1/3 - x/8 = x
(4x - 3x - 24 x )/24 = -1/3
-23x/24 = -1/3
x = 1/3 * 24/23 = 8/23approx 20 mins
Time it is filled
11: 20
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