Math, asked by Aditya9348, 11 months ago

Tap A is 50% more efficient than Tap B. Both the taps together can fill the tank in (48/5) hours. Find the time taken by Tap C which is 60%more efficient than Tap B, to fill the tank alone.

Answers

Answered by Anonymous
0

Time taken by Tap C alone to fill the tank is 48 hours.

Step-by-step explanation:

Let the time taken by Tap A to fill the tank alone is x hours.

Given:

  • Tap A is 50% more efficient than Tap B.

 =  > A = x \: hrs \\  =  >   \: B  =  \frac{x}{0.5} hrs \\  =  > B = 2x \: hrs

  • Both the taps together can fill the tank in (48/5) hours.

 =  >   \frac{1}{A}  +  \frac{1}{B}  =  \frac{5}{48}  \\  =  >  \frac{1}{x}  +  \frac{1}{2x}  =  \frac{5}{48}  \\  =  >  \frac{3}{2x}  =  \frac{5}{48}  \\  =  > x =  \frac{72}{5} hrs

  • Tap C which is 60%more efficient than Tap B.

 =  >  B = 2x \\  =  > B =  \frac{144}{5} hrs \\  =  > C =  \frac{B}{0.6} hrs \\  =  > C =  \frac{5B}{3} hrs \\  =  > C =  \frac{5}{3}  \times  \frac{144}{5} hrs \\  =  > C = 48 \: hrs

Time taken by Tap C alone to fill the tank is 48 hours.

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