Taps A and B can fill a tank in 20 and 30 minutes respectively. Both the taps are opened to fill the tank but when the tank was 1/3rd full then a leak develops in the bottom of the tank. Through which 1/3rd of water supply by both the pipes leak out . Then calculate in how much time the tank will fill ?
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Efficiency of first pipe = 100/20 = 5% per hour.
Efficiency of second Pipe = 100/30 = 3.33% per hour.
Efficiency of both pipe together = 5 + 3.33 = 8.33% per hour.
1/3 i.e. 33.33% tank be filled by these two pipes in = 33.33/8.33 = 4 hours.
Now, tank is empty and it need to be filled from zero. So
Time taken to Fill the empty tank = 100/8.33 = 12 hours.
So, Total time taken to filled the tank = 4 + 12 = 16 hours
Efficiency of second Pipe = 100/30 = 3.33% per hour.
Efficiency of both pipe together = 5 + 3.33 = 8.33% per hour.
1/3 i.e. 33.33% tank be filled by these two pipes in = 33.33/8.33 = 4 hours.
Now, tank is empty and it need to be filled from zero. So
Time taken to Fill the empty tank = 100/8.33 = 12 hours.
So, Total time taken to filled the tank = 4 + 12 = 16 hours
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