Question

Taps A and B can fill an empty tank in 12 hours and 16 hours, respectively. Tap C can empty the full tank in 8 hours. Working simultaneously, in how many hours can the taps fill the tank?

(With steps please and no inappropriate answers, Thank you :D)

Answer 1

Step-by-step explanation:

A can fill the tank in 12hrs

B can fill the tank in 16hrs

C empty the tank in 8hrs, here C doing negative work.

so assuming that the capacity of tank is

LCM of 12,16,8=48 parts

A can fill the tank in 1hr=48/12=4 parts

B can fill the tank in 1hr=48/16=3 part

C can empty the tank in 1hr=48/8=6 parts

So,the avg of water filled in tank is ,4+3-6=1 part

so, total time taken to fill the tank,if 3 taps are working simultaneously is =48/1=48hrs

Answer 2

Answer:

the full answers is 48 by 13