Math, asked by Anonymous, 6 months ago

तर cot2θ =? If sinθ = 4/5 , then cot2θ =? *​

Answers

Answered by MaheswariS
1

\underline{\textsf{Given:}}

\mathsf{sin\theta=\dfrac{4}{5}}

\underline{\textsf{To find:}}

\textsf{The value of}

\mathsf{cot\,2\theta}

\underline{\textsf{Solution:}}

\textsf{Using the identity,}

\boxed{\mathsf{tan2A=\dfrac{2\,tanA}{1-tan^2A}}}

\mathsf{tan2\theta=\dfrac{2\,tan\theta}{1-tan^2\theta}}

\mathsf{tan2\theta=\dfrac{2(\dfrac{4}{5})}{1-(\dfrac{4}{5})^2}}

\mathsf{tan2\theta=\dfrac{\dfrac{8}{5}}{1-\dfrac{16}{25}}}

\mathsf{tan2\theta=\dfrac{\dfrac{8}{5}}{\dfrac{25-16}{25}}}

\mathsf{tan2\theta=\dfrac{\dfrac{8}{5}}{\dfrac{9}{25}}}

\mathsf{tan2\theta=\dfrac{8}{5}{\times}\dfrac{25}{9}}

\mathsf{tan2\theta=8{\times}\dfrac{5}{9}}

\mathsf{tan2\theta=\dfrac{40}{9}}

\textsf{Now}

\mathsf{cot\,2\theta}

\mathsf{=\dfrac{1}{tan\,2\theta}}

\mathsf{=\dfrac{1}{40/9}}

\mathsf{=\dfrac{9}{40}}

\underline{\textsf{Answer:}}

\textsf{The value of}\;\mathsf{cot2\theta}

\textsf{is}\;\mathsf{\dfrac{9}{40}}

Answered by MinotiSharma
3

Answer:

Hogaya na bhaiya......

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