Question

तरंग सदिश को व्यक्त किया जाता है :
(i) 0
(ii) c=U
__(i) c
(iv) k=--
शुद्ध जल के लिए निरपेक्ष अपवर्तनांक का मान होता है
(i) 1.33
(ii) 1.5
(iii) 2.51
(iv) 1.0
परमाणु क्रमांक से तात्पर्य है :​

Answer 1

Answer:

1. Wave vector is the angular wave number given by K

2. refractive index of pure water is 1.33

3. Atomic number is total number of protons present in it

Explanation:

1. Wave number

in the given equation of wave the wave number is

$y = A sin(\omega t \pm kx + \phi)$

here we know that

$k = \frac{2\pi}{\almbda}$

so angular wave number of wave vector is "k"

2. Relative refractive index of pure water is given as

$\mu_w = \frac{c_{air}}{c_{water}}$

so we have

$\mu_w = \frac{4}{3} = 1.33$

3. Atomic number is total number of protons present in the given atom

so atomic number is the presentation of total protons in the given atom.

#Learn

Topic : Wave, Refractive index and Atomic structure

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