Math, asked by indrajith2005, 11 months ago

Tariq changed 22 into 5p, 20p and 50 p coins. If the number of 5 p coins was double the number
of 20p coins, and the 50p coins were one-fifth of the 20 p coins, how many coins of each
denomination did he get.​

Answers

Answered by acv49
0

Answer:

Say he had

1 coin of 50p

5 of 20p

and 10 of 5p

Step-by-step explanation:

so he had (1*50)+(5*20)+(10*5) p

=50+100+50=200p

= ₹ 2 or £ 2

But we want to make 22 rupees or £

so take 11 times more of each denomination

and we get

11c of 50p,

55c of 20p,

and

110c of 5p....ANSWER

Answered by lakshmananaditi001
1

Answer:

Say he had

1 coin of 50p

5 of 20p

and 10 of 5p

Step-by-step explanation:

so he had (1*50)+(5*20)+(10*5) p

=50+100+50=200p

= ₹ 2 or £ 2

But we want to make 22 rupees or £

so take 11 times more of each denomination

and we get

11c of 50p,

55c of 20p,

and

110c of 5p....ANSWER

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