Math, asked by Navdeeptarigopula, 3 months ago

Tarun and Arun go jogging in the morning. Arun jogs
around a rectangular field of length 100m and breadth is
300m. Tarun jogs around a square field of 15 m. who jogs
more and how much

Answers

Answered by Eutuxia
5

Before, finding the answer. Let's find out on how we can find the answer.

  • First, we must find the perimeter of the rectanglular field by using the formula of :

 \boxed{ \sf Perimeter  \: of \:  Rectangle  = (2 \times l )+ (2 \times b)}

  • Next, we must find the perimeter of Square Field by using the formula of

 \boxed{ \sf Perimeter  \: of  \: Square = 4 \times a}

  • Now, we must subtract the Perimeter of Rectangle from Perimeter of Square.

_____________________________

Given :

  • Length & Breadth of Rectangle = 100 m and 300 m.
  • Side of Square = 15 m.

To find :

  • who has covered more distance by how much.

Solution :

Perimeter of Rectangle = (2 × l) + (2 × b)

= (2 × 100) + (2 × 300)

= 200 + 600 sq.units

= 800 sq.m

Hence, the Perimeter of Rectangular Field is 800 sq.m

Perimeter of Square = 4 × s

= 4 × 15 sq.m

= 60 sq.m

Hence, the Perimeter of Square is 60 sq.m

Difference = 800 - 60 m

= 740 m

Arun jogs more than Tarun by 740 m.

Answered by Anonymous
2

Given:

  • Length and Breadth of Rectangle = 100 m and 300 m respectively.
  • Side of a square = 15 m.

To find:

Who has covered the more distance and by how much difference.

Solution:

We know that,

\quad {\underline{\boxed{\sf Perimeter \ of \ rectangle \ = \ (2 \times l) + (2 \times b)}}}

\implies \sf (2 \times 100) + (2 \times 300)

\implies \sf 200 + 600 \ sq.units

\implies \sf 800 \ sq.m

\therefore The perimeter of the rectangle is 800 sq.m.

Now,

Perimeter of square = 4 × s

\implies \sf 4 \times 15 \ sq.m

\implies \sf 60 \ sq.m

\therefore The perimeter of square is 60 sq.m.

Now,

Difference = 800 - 60 m

= 740 m

\therefore Arun jogs more than Tarun by 740 m.

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