Tarun bought a few pens, pencils, and erasers (at least one of each type). Each pen costs Rs. 7, each pencil costs Rs. 5 and each eraser costs Rs. 4. Which of the
following cannot be the total number of pen, pencil, and eraser that Tarun has bought if he spent Rs. 100 for purchasing them?
Answers
Given : Tarun bought a few pens, pencils, and erasers (at least one of each type).
Each pen costs Rs. 7, each pencil costs Rs. 5 and each eraser costs Rs. 4.
To Find : Which cannot be the total number of pen, pencil, and eraser that Tarun has bought if he spent Rs. 100 for purchasing them
Solution:
Pen bought = A
pencil bought = B
Eraser Bought = C
Total cost = 7A + 5B + 4C = 100
7A + 4C = 100 - 5B
7A + 4C =5 (20 - B)
7A + 4C = 5k
=> 7A - C = 5(k - C)
Total
A = 1 => C = 2 and B = 17 Total 20
A = 1 => C = 7 and B = 13 Total 21
A = 1 => C = 12 and B = 9 Total 22
A = 1 => C = 17 and B = 5 Total 23
A = 1 => C = 22 and B = 1 Total 24
A = 2 => C = 4 and B = 14 Total 20
A = 2 => C = 9 and B = 10 Total 21
A = 2 => C = 14 and B = 6 Total 22
A = 2 => C = 19 and B = 2 Total 20
A = 3 => C = 1 and B = 15 Total 19
A = 3 => C = 6 and B = 11 Total 20
A = 3 => C = 11 and B = 7 Total 21
A = 3 => C = 16 and B = 3 Total 22
A = 4=> C = 3 and B = 12 Total 19
A = 4 => C = 8 and B = 8 Total 20
A = 4 => C = 13 and B = 4 Total 21
A = 5=> C = 5 and B = 9 Total 19
A = 5 => C = 10 and B = 5 Total 20
A = 5 => C = 15 and B = 5 Total 21
A = 6=> C = 2 and B = 10 Total 18
A = 6 => C = 7 and B = 6 Total 19
A = 6 => C = 12 and B = 2 Total 20
A =7=> C = 4 and B = 7 Total 18
A = 7 => C =9 and B = 3 Total 19
A =8=> C = 1 and B = 8 Total 17
A = 8 => C =6 and B = 4 Total 18
A =9=> C = 3 and B = 5 Total 17
A = 9 => C =8 and B = 1 Total 18
A =10 => C = 5 and B = 2 Total 17
A =11 => C = 2 and B = 3 Total 16
A =12 => C = 4 and B = 0 ( not possible)
A =13 => C = 1 and B = 1 Total 15
Hence can buy from 15 to 24 items
Any option which is other than from 15 to 24 can not be purchased.
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