Tarun read 3/8 of a book on one day and 4/5of the reminder another day.if there are 30 pages unread then how many pages did the book contain
Answers
Answered by
31
Let the total number of pages be 'x'
3/8x on first day
Remaining = [8x - 3x]/8 = 5/8x
4/5 of 5/8x = 1/2x
A/Q ---.>
3/8x + 1/2x + 30 = x
7/8x - x = -30
- 1/8x = -30
x = 240
So required answer is 240 pages.
Hope This Helps You!
3/8x on first day
Remaining = [8x - 3x]/8 = 5/8x
4/5 of 5/8x = 1/2x
A/Q ---.>
3/8x + 1/2x + 30 = x
7/8x - x = -30
- 1/8x = -30
x = 240
So required answer is 240 pages.
Hope This Helps You!
Answered by
18
HI !
Let the total number of pages be ''x''
3/8 pages was read on the first day
Remaining pages = 8x - 3x/8 = 5/8x
4/5 of 5/8x = 1/2x
as per the qn ,
3/8x + 1/2 x + 30 = x
7/8x - x = -30
- 1/8x = -30
x = 240
Total no: of pages = 240
Let the total number of pages be ''x''
3/8 pages was read on the first day
Remaining pages = 8x - 3x/8 = 5/8x
4/5 of 5/8x = 1/2x
as per the qn ,
3/8x + 1/2 x + 30 = x
7/8x - x = -30
- 1/8x = -30
x = 240
Total no: of pages = 240
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