Question

Tarun works as twice as much as Mihir both of them finish the work in 12 days Tarun alone can do it in​

Answer 1

Question :-

Tarun works as twice as much as Mihir both of them finish the work in 12 days . Tarun alone can do it in how many days ?

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Given :-

• Tarun works twice more than Mihir.
• Mihir works twice less than Tarun.
• Both of them can finish the work in 12 days.

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Find :-

• Tarun alone can do the work in how Many days.

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How to solve ?

Here we first have to make a ratio of both their work then, we also don't know how much the work is done by both of them . So, we also need to find total work and then simply calculate the work done alone by Tarun .

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Solution :-

• Let work done by mihir be X
• Let work done by Tarun be 2X

⟹ X + 2X = 12

⟹ 3X = 12

⟹ X = 12/3

⟹ X = 4

In X Now put the values

1. Mihir work = X = 4
2. Tarun work = 2X = 8

Ratio :-

Therefore , their ratio becomes

Mihir : Tarun

4 : 8

Now, making ratio simplifyied

Mihir : Tarun

1 : 2

• Tarun + Mihir = 12 days

Total work

$\rm \implies12 \times (2 + 1)$

$\rm \implies12 \times3$

$\rm \implies36 \: units$

Therefore,

Tapas can complete the work in

$\rm \: 2x = 36$

$\sf x = \cancel \dfrac{36}{2} = 18 \: days$

$\sf {\huge \therefore}\:Tapas\: can\: complete\: the \:same\: work\: in\: \bf 18 \:days\:$

Mihir can complete the work in

$\rm \: x = 36$

$\sf {\huge \therefore}\:Mihir\: can\: complete\: the \:same\: work\: in\:\bf 36 \:days\:$

From the above we can also understand that who does how much unit of work per day .

• Tapas does 2 unit of work per day and so that's why he complete work within 18 days.

Whereas,

• Mihir does 1 unit of work per day and so that's why he complete work in 36 days.

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