Question

Task 2: Art is twice as old as Ken. Five years ago, he was three times as old as Ken. Write
the algebraic equation for their ages five years ago.​

Answer 1

Step-by-step explanation:

Given:-

Art is twice as old as Ken. Five years ago, he was three times as old as Ken.

To find:-

Write the algebraic equation for their ages five years ago.

Solution:-

Let the present age of Ken be X years

Then the present age of Art = twice as old as Ken

= 2X years

Five years ago their ages would be

Age of Ken = (X-5) years

Age of Art = (2X-5) years

Given that

Five years ago, he was three times as old as Ken

Age of Art = 3× Age of Ken

=> (2X -5) = 3×(X-5)

=> 2X - 5 = 3X - 15

=> 3X - 15 - 2X + 5 = 0

=> (3X -2X ) +(-15+5)=0

=> X +(-10) = 0

=> X - 10 = 0

Answer:-

The required algebraic equation for finding their ages is X - 10 = 0