Taxi charges consist of fixed charges per day and the remaining depending upon the distance travelled in kilo meters . If a person travels 110 km, he pays Rs.690 and for travelling 200 km,he pays Rs. 1,050. Express the above statements in the form of simultaneous equations and hence, find the fixed charges per day and the rate per km.
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Let fixed charges and charge per Km be x and y respectively
then,
x+110y=690⇒1 and x+200y=1050⇒2
solving 1 and 2
+x+110y=690
+ x+200y=1050
(-) (-) (-)
____________
-90y=-360
y=360/90
y=Rs4
substiuting y in 1
x+110y=690
x+110*4=690
x=250
Therefore fixed charge=250 and charge per Km = 4
then,
x+110y=690⇒1 and x+200y=1050⇒2
solving 1 and 2
+x+110y=690
+ x+200y=1050
(-) (-) (-)
____________
-90y=-360
y=360/90
y=Rs4
substiuting y in 1
x+110y=690
x+110*4=690
x=250
Therefore fixed charge=250 and charge per Km = 4
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