Question

Taxi charges in a city consist of fixed charges and the remaining charges
depend upon the distance travelled. For a journey of 10 km, the charge
paid is * 75 and for a journey of 15 km, the charge paid is 110. Find
the fixed charge and charges per km. Hence, find the charge of covering a
distance of 35 km.​

Answer 1

Given :-

• 10km = Rs.75.
• 15km = Rs.110

To find :-

• Charge for 35km ?

Solution :-

→ Let us assume That, fixed charge is = Rs.x

→ And, Than, Charge per km = Rs.y .

Than, A/q,

→ x + 10y = 75 --------- Equation (1)

→ x + 15y = 110 --------- Equation (2)

Subtracting Equation (1) From Equation (2) , we get,

→ (x + 15y) - (x + 10y) = 110 - 75

→ x - x + 15y - 10y = 35

→ 5y = 35

→ y = 7 .

Putting in Equation (1) we get,

→ x + 10*7 = 75

→ x = 75 - 70

→ x = 5.

Hence, The fixed charge is = Rs.5 .

→ Charge per km is = Rs.7.

And ,

→ the charge of covering a distance of 35 km. = 5 + 35*7 = 5 + 245 = Rs.250 .

Hence, the charge of covering a distance of 35 km is Rs.250.

Answer 2

Given:-

Cost charged for 10 km of journey = ₹ 75

Cost charged for 15 km of journey = ₹ 110

To find:-

Cost charged for 35 km of journey.

Solution:-

Let the fixed charge be ₹ x.

Let the charge per km be ₹ y.

A/q,

x + 10y = 75                ...(i)

x + 15y = 110               ...(ii)

On subtracting eq.(i) from (ii):

 x + 15y = 110

-

 x + 10y = 75

_____________

      5y = 35

y = 35/5

$\boxed{y = 7}$

Now, putting y = 7 in eq.(ii):

x + 10y = 75

⇒x + 10*7 = 75

⇒x = 75 - 70

$\boxed{x=5}$

∴The fixed charge is ₹ 5 and the charge per km is ₹ 7.

Now, the charge of covering 35 km will be x + 35y

= 5 + 35*7

= 5 + 245

= ₹250.

∴Hence, the charge of covering a distance of 35 km is ₹250.