Taxi fare aftere each Km when the fare is 15Rs for the first km and 8m for each additional fare . Is this an arithmetic progression ?if so what is the value of a and d ?
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Answered by
3
t
Answer:
Correct option is
A
0
The taxi fare for first km=15
The taxi fare for 2nd km=15+8=23
The taxi fare for 3rd km=15+8+8=31 and so on,
Therefore, the taxi fare form the sequence 15,23,31,...
Clearly, it is an AP with first term a=15 and common difference d=8
Therefore, answer is 0.
Answered by
1
Answer:
15 for the first km and Rs 8 for each additional km, dies not form an A.P., as the total fare (in Rs) after each km is 15, 8, 8, 8,.... Is the statement true ∵ Give reasons.
Step-by-step explanation:
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