Question

Taxi fare consist of a constant charge together with the charge for the distance covered. A person travelling 15 km pays Rs115 for the journey and a person travelling 27km pays Rs199 for it. Find the charges one will have to pay for a journey of 50km.

Answer 1

Answer:

Solution:-

Let the constant charge be Rs. x and the charge per km be Rs. y

According to the first condition,

x+15y = 115 ....(1)

Second condition,

x+27y = 199 ....(2)

Now subtracting equation (1) from (2),

 x+27y = 199

 x+15y = 115

-  -         - 

__________

  12y =  84

y = 84/12

y = 7

Therefore putting the value of x in equation (1), we get

x+(15 × 7) = 115

x+105 = 115

x = 115 - 105

x = 10

Therefore the constant charges for the taxi is Rs.10 and

charge per km is Rs. 7  Answer

Answer 2

$\large \bold{ \underline{ \underline{ \: Answer : \: \: \: }}}$

$\to$ The constant charge = Rs 10

$\to$ The charge per km = Rs 7

$\large \bold{ \underline{ \underline{ \: Solution : \: \: \: }}}$

Let ,

$\to$ The constant charge = Rs x

$\to$ The charge per km = Rs y

First condition ,

x + 15y = 115 ----- (i)

Second condition ,

x + 27y = 199 ----- (ii)

Subtract equation (1) from (2) ,

we get ,

$\to$ x + 27y - (x + 15y) = 199 - 115

$\to$ 12y = 84

$\to$ y = 84/12

$\to$ y = 7

Put the value of y = 7 in eq (i)

$\to$ x + (15 × 7) = 115

$\to$ x + 105 = 115

$\to$ x = 115 - 105

$\to$ x = 10

$\therefore$ The constant charge of taxi is Rs 10 and charge per km is Rs 7