Taxi fare in a city consits of a constant charge together with a charge for the distance covered. Ritika paid rs 82 for 15km and Monica paid rs. 142 for 27km find the charge they had to pay for 50 km
Answers
Answered by
1
Answer:
Answer is 535.5 RS they had to pay
Step-by-step explanation:
ritika paid RS 82 for 15 km
Monica paid RS 142 for 27 km
- RS paid by ritika for 1 km = 82/15= 5.46 RS/km
- RS paid by Monica for 1 km= 142/27= 5.25 RS/km
= so now fare charge of ritika for 50 km
5.46×50= 273 RS
= now fare charge of Monica for 50 km
5.25×50= 262.5 RS
By adding both fares we get
273+262.5= 535.5 RS
Answered by
1
hey mate here is the solution.
check it out.
Attachments:
Similar questions