Math, asked by divyanshumakhija2004, 10 months ago

Taxi fare in a city consits of a constant charge together with a charge for the distance covered. Ritika paid rs 82 for 15km and Monica paid rs. 142 for 27km find the charge they had to pay for 50 km

Answers

Answered by shashikantkumar15
1

Answer:

Answer is 535.5 RS they had to pay

Step-by-step explanation:

ritika paid RS 82 for 15 km

Monica paid RS 142 for 27 km

- RS paid by ritika for 1 km = 82/15= 5.46 RS/km

- RS paid by Monica for 1 km= 142/27= 5.25 RS/km

= so now fare charge of ritika for 50 km

5.46×50= 273 RS

= now fare charge of Monica for 50 km

5.25×50= 262.5 RS

By adding both fares we get

273+262.5= 535.5 RS

Answered by tushar00791
1

hey mate here is the solution.

check it out.

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