Math, asked by latasable1111, 7 months ago

taxi fare in a city is as follows for the first kilometre the fare is rupees 8 in for the subsequent distance it is rupees 5 per kilometre taking the distance covered with X kilometre and total for rupees UAE write a linear equation for this information​

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Answered by prashantjha710
4

Answer:

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Answered by nzptsix380
0

Answer:

Solution:

Given: The distance covered is x km and the total fare is ₹ y. Also, the fare of the first kilometre is ₹ 8 and for the subsequent distance, it is ₹5 per km.

Let the total distance covered = x km

Therefore, subsequent distance = (x - 1) km

The total fare covered = ₹ y

Fare for the 1st kilometre = ₹ 8

Fare per km = ₹ 5

Fare rate for the subsequent distance = 5(x - 1)

The linear equation for the above information is given by,

Total fare = Fare for the first kilometre + Subsequent distance × Fare per km

y = 8 + (x - 1) 5  

y = 8 + 5x - 5

y = 5x + 3

5x - y + 3 = 0

This can be written as,

y = 5x + 3  ---  Equation (1)

By substituting different values of x in Equation (1) we get different values for y.

When x = 0, y = 5 × 0 + 3 = 0 + 3 = 3

When x = 1, y = 5 × (1) + 3 = 5 + 3 = 8

When x = 2, y = 5 × (2) + 3 = 10 + 3 = 13

When x = -1, y = 5 × (-1) + 3 = -5 + 3 = -2

When x = -2, y = 5 × (-2) + 3 = -10 + 3 = -7

Thus, we have the following table with all the obtained solutions:

x

0

1

2

-1

-2

y

3

8

13

-2

-7

By Plotting the points (0, 3), (1, 8), (2, 13), (-1, -2) and (-2, -7) on the graph paper and drawing a line joining them, we obtain the required graph.

The graph of the line represented by the given equation 5x - y + 3 = 0   is shown below:

The taxi fare in a city is as follows: For the first kilometre, the fare is ₹ 8 and for the subsequent distance it is ₹ 5 per km. Taking the distance covered as x km and total fare as ₹ y, write a linear equation for this information, and draw its graph

Here, the variables x and y are representing the distance covered and the fare paid for that distance respectively, and these quantities cannot be negative.

Hence, only those values of x and y which are lying in the 1st quadrant will be considered as they are positive.

Step-by-step explanation:

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