Math, asked by AngelMariyaJose, 4 months ago

taylor series expansion on tan (pi/4+x)

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Answered by sumanpreet2012005

Answer:

1 f'(π/4) = 2 a1 = 2/1! = 2f''(π/4) = 4 a2 = 4/2! = 2f'''(π/4) = 16 a3 = 16/3! = 8/3From this we can conclude tan(x) = 1 + 2(x-π/4) + 2(x-π/4)2 + (8/3)(x-π/4)^3.

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taylor series expansion on tan (pi/4+x)​

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taylor series expansion on tan (pi/4+x)