Question

tbe two arms of a balance are of unequal length. an object when placed in the left pan of the balance weights 4kg. the same object when placed in the right pan of the balance weighs9kg.the actual mass of the object​

Answer 1

Given:  Two arms of a balance are of unequal length.

To find: The actual mass of the object​.

Solution:

• Now lets consider the mass of the body as m and let the lengths of the hangs of the balance be x and y.

• Now according to question, first, the object is kept on the x- side of the balance. So when object is kept in x- side, it weighs 4 kg.

• Moments of the forces about the balance are equal

• So, m (x) = 4 (y)

• Similarly, in the next case 9 (x) = m (y)

• So now, dividing both the equations, we get:

             m / 9 = 4 / m

             m² = 36

              m = 6 kg

• So the weight or actual mass will be:

           = 6 x 9.8

           = 58.8 N

Answer:

           The actual mass of the object​ is 58.8 N.