Computer Science, asked by krkannamrajashekar, 20 days ago

TCS OFF CAMPUS ASSESSMENT TCS Off Campus Jan 2022 8th S2 View Instruction Numerical Ability i Verbal Ability Reasoning Ability Part A - Test of Kno Part B - Test of App...i LUP Time Left: 22:40 Section Numerical Ability i Answered 12 Not Answered Question No. 13 13 Not Visited 0 Marked for Review Note: You cannot revisit this question upon navigating. Please take care not to move to previousinext question without attempting this Question. Answered & Marked for Review (will be considered for evaluation Numerical Ability The price of branded TV and assembled TV is in the ratio of 81 16. If from now on every year the price of branded TV goes on decreasing by 20% and the price of assembled TV goes on increasing by 20%, then after how many years will the price of both be equal? Choose a Question 03 14 15 5 16 5 19 20 17 18 6 23 24 21 22 25 26 Sub Save & Next Version 17.07.00
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Answers

Answered by badboi928

Answer:

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Answered by surajnegi0600

Answer:

This can be determined using an equation. Let x be the number of years it takes for the prices to be equal.

(81/97) * (0.8)^x = (16/97) * (1.2)^x

Explanation:

You can solve this equation for x by isolating it on one side and taking the natural logarithm of both sides.

x = ln((16/97) / (81/97)) / ln(0.8/1.2)

which is equal to approx. 3.17 years.

The equation uses the initial ratio of the prices 81:16 and the fact that the price of branded TV decreases by 20% every year while the price of the assembled TV increases by 20% every year. By isolating x and taking the natural logarithm of both sides, we can find an approximate value for x, which is approximately 3.17 years. It means, after 3.17 years the price of both TVs will be equal. This is an approximate value as the prices depend on the initial prices and the constant percentage change in prices over time.