Question

Te sum of two numbers is 8 and the sum of their squares is 34. Taking one number as x

form an equation in x and hence find the numbers. The numbers are​

Answer 1

Answer:

3 & 5

Step-by-step explanation:

Let one number be x.

Then, the other number is (8 - x).

ATQ,

$x^{2} + (8 - x)^{2} = 34\\x^{2} + 64 - 16x + x^{2} = 34\\2x^{2} - 16x + 64 - 34 = 0\\2x^{2} - 16x + 30 = 0\\2(x^{2} - 8x + 15) = 0\\x^{2} - 8x + 15 = 0\\x^{2} - 5x - 3x + 15 = 0\\x(x - 5) - 3(x - 5) = 0\\(x - 3)(x - 5) = 0$

x - 3 = 0       x - 5 = 0

x = 3             x = 5

We can consider x to be 3

∴ One of the numbers = x = 3

∴ The another number = 8 - x = 8 - 3 = 5

∴The two numbers are 3 & 5.

PLEASE MARK BRAINLIEST...

Answer 2

If not in 2 variables then x=8-y and x2+y2=34