Question

te the answers of the following questions:
1) The measure of four angles of a quadrilateral are 3x, 4x, 5x and 6x. find all the
angles.​

Answer 1

3x + 4x+5x+6x= 360

18x =360

x= 20

First angle = 3x = 3×20=60

Second angle= 4x= 4×20=80

Third angle = 5x=5×20 = 100

Fourth angle = 6x= 6×20=120

Answer 2

Answer:

$\huge \bf \: given$

[tex]\begin {cases}1st side of quadrilateral = 3x \\ 2nd side of quadrilateral = 4x \\ 3rd side of quadrilateral = 5x \\ 4th side of quadrilateral = 6x\end {cases}[/tex]

$\huge \bf \: to \: find$

Angle of all sides

$\huge \bf \: solution$

As we know that sum of all sides of quadrilateral = 360⁰

Sum of the sides given = 3x + 4x + 5x + 6x = 18x

$18x = 360$

$x = \frac{360}{18}$

$x = 20$

$3x = 3 \times 20 = 60$

$4x = 4 \times 20 = 80$

$5x = 5 \times 20 = 100$

$6x = 6 \times 20 = 120$

Verification

60⁰+80⁰+100⁰ +120⁰ = 360⁰

140⁰+220⁰ = 360⁰

360⁰=360⁰

LHS = RHS