Question

TE
Tom walks 6 km east. Then he turns to his right and walks 10 km. He turns to his right and walks 6 km.
He then turns left and walks 15 km. At what distance and in which direction is he from the starting
point?​

Answer 1

Answer:

South direction he walks

Answer 2

Given:

Tom walks 6km east, then turns right and walks another 10km, and then finally he turns left and walks another 15km.

To Find:

The distance of Tom from the initial point to the final point.

Solution:

1. It is given that Tom initially walks 6km towards the east. Now Tom is at a distance of 6km from the starting point.

2. After walking 6km towards the east, Tom turns right and walks for another 10km implies, Tom has walked another 10km towards the north. The total distance traveled by tom till this point is 16km.

3. The shortest distance between the initial point and the present point can be formulated using the Pythagoras theorem.

• Shortest distance = $\sqrt{(East side distance)^{2} +(North side distance)^{2} }$,

=> Shortest distance = $\sqrt{100+ 36}$,

=> Shortest distance from the starting point = $\sqrt{136}$ km.

4. Tom now walks 6 more kilometers towards his right, which implies Tom walks 6km towards the west. The distance walked by Tom towards the east and the west is the same. Hence  Logically it can also be considered as  Tom just walking 10Km towards the North as of now.

5. Finally Tom turns left and walks 15km, which implies Tom has started walking towards the north and has traveled 15km.

• From point 4 it is clear that Tom is now at a distance of 10km from the initial point towards the north.
• In the final walk, Tom had walked 15 more kilometers towards the north, Therefore the final distance at which tom is currently standing from the starting point is 25 km and he is facing the north direction finally.

Hence, Tom is at a distance of 25km from the starting point and facing towards the north.