Question

Technical) Exam. 27.02.2011)
3. A particular job can be completed
by a team of 10 men in 12 days.
The same job can be completed
by a team of 10 women in 6 days.
How many days are needed to
complete the job if the two teams
work together?

Answer 1

Answer:

According to the question,

10 men’s one day’s work = \frac{1}{12}

∴ 1 man one day’s work = \frac{1}{12\times 10} = \frac{1}{120}

Similarly,

1 woman one day’s work = \frac{1}{6\times 10} = \frac{1}{60}

∴ (1 man + 1 woman)’s one day’s work = \frac{1}{120}+\frac{1}{60}

= \frac{1+2}{120} = \frac{3}{120} = \frac{1}{40}

∴ (10 man + 10 woman)’s one day’s work = \frac{10}{40} = \frac{1}{4}

Therefore, both the team can finish the whole work in 4 days.