Question

Ted had two ribbons of lengths 1 1/4 m and 2 3/8 m. He used 1 1/2 m ribbon to decorate his room. What is the length of the ribbon left with him?

Answer 1

Given :-

Length of the two ribbons Ted had :-

$=\texttt{ 1} \frac{\texttt{1}}{\texttt{4}} \texttt{\: m \: and \: 2}\frac{\texttt{3}}{\texttt{8}} \texttt{\: m}$

$=\texttt{1}\frac{\texttt{1}}{\texttt{4}} \texttt{ \: + \: } \texttt{2}\frac{\texttt{3}}{\texttt{8} }$

$= \frac{\texttt{(4 \: × \: 1 + 1)}}{\texttt{4}} \texttt{ \: + \: } \frac{\texttt{(8 \: × \: 2 + 3)}}{\texttt{8} }$

$= \frac{\texttt{5}}{\texttt{4}} \texttt{ \: + \: } \frac{\texttt{19}}{\texttt{8} }$

$= \frac{\texttt{(5×2)}}{\texttt{8}} \texttt{ \: + \: } \frac{\texttt{(19×1)}}{\texttt{8} }$

$= \frac{\texttt{\texttt{10}}}{\texttt{8} } \texttt{ \: + \: } \frac{\texttt{19}}{\texttt{8} }$

$= \frac{\texttt{29}}{\texttt{8}}$

$= \color{j}\texttt{3} \frac{\texttt{5}}{\texttt{8} } \: \texttt{m}$

Thus, the total length of ribbons Ted had :-

$=\color{hotpink}\texttt{ 3} \frac{\texttt{5}}{\texttt{8}} \: \:\texttt{m}$

Length of ribbon Ted used for decorating his room :-

$=\texttt{ 1} \frac{\texttt{1}}{\texttt{2}} \texttt{\: \: m}$

$= \frac{\texttt{(2 × 1 + 1)}}{\texttt{2}}$

$= \frac{\texttt{(2 + 1)}}{\texttt{2} }$

$= \frac{\texttt{3}}{\texttt{2}} \texttt{ \: m}$

Thus the length of ribbon Ted used :-

$= \color{hotpink} \frac{\texttt{3}}{\texttt{2}} \texttt{ \: m}$

Length of ribbon left with Ted :-

$= \frac{\texttt{39}}{\texttt{8}} \texttt{ \: - \: } \frac{\texttt{3}}{\texttt{2} }$

$= \frac{\texttt{(39×1)}}{\texttt{8}} \texttt{ \: - \: } \frac{\texttt{(3×4)}}{\texttt{8} }$

$= \frac{\texttt{39}}{\texttt{8}} \texttt{ - } \frac{\texttt{12}}{\texttt{8} }$

$= \frac{\texttt{27}}{\texttt{8} }$

$= \color{rck}\texttt{3}\frac{\texttt{3}}{\texttt{8} } \: \texttt{ \: m}$

Therefore, the length of ribbon left with Ted is :-

$= \bold{ \color{hotpink}\texttt{3}\frac{\texttt{3}}{\texttt{8} } \: \texttt{ \: m}}$

Answer 2

Answer:

17/8 or 2 1/8

Step-by-step explanation: