Question

Teena is 3 years younger than his brother. If the sum of their ages is 32 years. What are
their present ages?

Answer 1

Answer:

Given ,

sum of their ages = 32

To find : 1) age of Teena and his brother .

Step-by-step explanation:

Let the age of Teena be 3x .

Let the age of Teena's brother be x.

3x + x = 32

4x = 32

x = 32/4

x = 8 Ans

So , the age of Teena = 3x = 3 x 8 = 24 years .

the of Teena's brother be x = 8 years .

Hence the age of Teena is 24 years and the age of her brother is 8 years..

Answer 2

Answer:

Teena 's present age is x years and her brother' s present age is

(x+3) years.

From given condition,

Sum of their ages is 32 years

x+(x+3)=32

2x+3=32

x=32-3/2

x=29/2

x=14.5

Teena's present age is 14.5 years and

Her brother's present age is (x+3)=14.5+3=17.5 years

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