Math, asked by neerajpargaiclass9a, 5 months ago

Teena is 3 years younger than his brother. If the sum of their ages is 32 years. What are their present ages.
answer in detail.​

Answers

Answered by Flaunt
56

\huge\bold{\gray{\sf{Answer:}}}

Explanation:

Given:

Teena is 3 years younger than his brother and the sum of their ages is 32 years.

To Find :

Their present ages

ㅤㅤㅤㅤㅤㅤㅤㅤ

ㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Let the teena's brother age be 'x'

Teena 's age then ='x-3'(because she is 3 years younger than his brother)

Now according to the question

Their sum of their ages is 32

 =  > x + x - 3 = 32

 =  > 2x - 3 = 32

 =  > 2x = 35

 =  > x =  \frac{35}{2}  = 17.5

Therefore ,Teena 's brother present age is 17.5 years

Now ,teena's present age is x-3=17.5-3=14.5 years

\bold{\red{\underline{Check :-}}}

sum of their ages :- 17.5

. 14.5

______

32.0

ㅤㅤㅤㅤㅤㅤㅤㅤ

Answered by Anonymous
2

\huge\bold{\gray{\sf{Answer:}}}

Explanation:

Given:

Teena is 3 years younger than his brother and the sum of their ages is 32 years.

To Find :

Their present ages

ㅤㅤㅤㅤㅤㅤㅤㅤ

ㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Let the teena's brother age be 'x'

Teena 's age then ='x-3'(because she is 3 years younger than his brother)

Now according to the question

Their sum of their ages is 32

 =  > x + x - 3 = 32

 =  > 2x - 3 = 32

 =  > 2x = 35

 =  > x =  \frac{35}{2}  = 17.5

Therefore ,Teena 's brother present age is 17.5 years

Now ,teena's present age is x-3=17.5-3=14.5 years

\bold{\red{\underline{Check :-}}}

sum of their ages :- 17.5

ㅤㅤㅤㅤㅤㅤㅤㅤㅤ. 14.5

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ______

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ 32.0

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

ㅤㅤㅤㅤㅤㅤㅤㅤ

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