Math, asked by shaibhafathima77, 2 months ago

Teena is 4 years younger than her brother. If the sum of their ages is 32, what are their present
ages?

Answers

Answered by bhoomimaurya2302
0

Answer:

let her brother's age be x years

Tina is 4 year younger = x - 4

According to given condition

sum of their age is 32

x+ x - 4 = 32

2x-4 = 32

2x= 32-4

2x= 28

x= 28/ 2

x = 14

brothers age = x = 14

Tina age = x-4

= 14-4

=10

Answered by mddinodshakya
0

Answer:

Step-by-step explanation:

2x-4=32

\frac{2x}{2}     = \frac{36}{2}

x=18

teena's age           =14

teena's broter age=18

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